第 35 关，删除重复项。指令集介绍请看：https://www.annhe.net/article-3828.html。
优化目标
17 行 167 步
代码
16行149步
见 Github。执行顺序很好，不用来回取变量
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start: INBOX JUMP out up: BUMPUP 14 COPYFROM 12 out: COPYTO [14] OUTBOX loop: COPYFROM 14 COPYTO 13 INBOX COPYTO 12 compare: SUB [13] JUMPZ loop BUMPDN 13 JUMPN up COPYFROM 12 JUMP compare |
15行177步
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start: INBOX COPYTO [14] out: COPYFROM [14] OUTBOX BUMPUP 14 up: COPYFROM 14 COPYTO 13 loop: INBOX COPYTO [14] compare: BUMPDN 13 JUMPN out COPYFROM [13] SUB [14] JUMPZ up JUMP compare |
21行161步
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init: INBOX COPYTO 0 OUTBOX COPYFROM 14 COPYTO 13 BUMPUP 13 JUMP loop out: COPYFROM [13] OUTBOX BUMPUP 13 loop: COPYFROM 14 COPYTO 12 INBOX COPYTO [13] compare: SUB [12] JUMPZ loop BUMPUP 12 SUB 13 JUMPZ out COPYFROM [13] JUMP compare |
第一次pass 25行224步
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COPYFROM 14 COPYTO 13 COPYTO 12 INBOX COPYTO 0 OUTBOX JUMP loop out: COPYFROM 11 OUTBOX reset: COPYFROM 14 COPYTO 12 loop: INBOX COPYTO 11 find: COPYFROM 13 SUB 12 JUMPN notfound COPYFROM [12] SUB 11 JUMPZ reset BUMPUP 12 JUMP find notfound: BUMPUP 13 COPYFROM 11 COPYTO [13] JUMP out |
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