PHP错误：Notice:Undefined variable: SCRIPT_NAME

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《php+mysql八大动态web应用实战》成书比较早，php中有些内容已经改变，如下代码：

if($_POST['submit']) {
	$db = mysql_connect($dbhost, $dbuser, $dbpassword);
	mysql_select_db($dbdatabase, $db);

	$sql = "INSERT INTO myblog_comments(blog_id, dateposted, name, comment) VALUES(" . $validentry . ", NOW(), '" . $_POST['name'] . "', '" . $_POST['comment'] . "');";
	mysql_query($sql);
	header("Location: http://". $HTTP_HOST . $SCRIPT_NAME . "?id=" . $validentry);
}

if($_POST['submit']) {

$db = mysql_connect($dbhost, $dbuser, $dbpassword);

mysql_select_db($dbdatabase, $db);

$sql = "INSERT INTO myblog_comments(blog_id, dateposted, name, comment) VALUES(" . $validentry . ", NOW(), '" . $_POST['name'] . "', '" . $_POST['comment'] . "');";

mysql_query($sql);

header("Location: http://". $HTTP_HOST . $SCRIPT_NAME . "?id=" . $validentry);

}

<form action="<?php echo $SCRIPT_NAME . "?id=" . $validentry; ?>" method="post">
<table>
<tr>
	<td>昵称</td>
	<td><input type="text" name="name"></td>
</tr>
<tr>
	<td valign="top">评论</td>
	<td><textarea name="comment" rows="10" cols="50"></textarea></td>
</tr>
<tr>
	<td></td>
	<td><input type="submit" name="submit" value="提交评论"></td>
</tr>
</table>
</form>

<form action="<?php echo $SCRIPT_NAME . "?id=" . $validentry; ?>" method="post">

<table>

<tr>

</tr>

<tr>

</tr>

<tr>

</tr>

</table>

</form>

会出现403错误，并在浏览器地址栏中报错如下：
Notice:Undefined variable: SCRIPT_NAME :…

$SCRIPT_NAME这个变量出了问题。网上搜了下，资料较少，没有搜到明确结果，不过看基本的写法都是 $_SERVER[‘SCRIPT_NAME’]，大概是写法变了。
把上面的代码中$HTTP_HOST和$SCRIPT_NAME改为$_SERVER[‘HTTP_HOST’]和$_SERVER[‘SCRIPT_NAME’]即可。

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PHP错误：Notice:Undefined variable: SCRIPT_NAME

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